JSON parse error: Cannot deserialize value of type java.util.ArrayList＜SalarySecurityDto＞ f解决方法

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Cannot deserialize value of type java.util.ArrayList<cn.wb.oa.server.salary.dto.SalarySecurityDto> from Object value (token JsonToken.START_OBJECT)

//报错原因大概意思是类型无法转换

//这是后端接收参数的方式
@RequestMapping(value = "/reset_batch", method = RequestMethod.POST)
    public ResultResponse<Boolean> resetSalarySecurityBatch(@RequestBody List<SalarySecurityDto> salarySecurityDto) {
    }

//这是后端传的参数
[
  {
    "schoolId": 21966,
    "userId": 845072,
    "securityCode": 999999,
    "modifyUser": "林某"
  },
  {
    "schoolId": 21966,
    "userId": 778563,
    "securityCode": 999999,
    "modifyUser": "林某"
  }
]
//接口没有报错

//这是前端传的参数
[
  {
    "schoolId": "W_SCHOOLID",
    "userId": "55410",
    "modifyUser": "林某",
    "securityCode": "111111"
  },
  {
    "schoolId": "W_SCHOOLID",
    "userId": "767028",
    "modifyUser": "林某",
    "securityCode": "111111"
  },
  {
    "schoolId": "W_SCHOOLID",
    "userId": "778490",
    "modifyUser": "林某",
    "securityCode": "111111"
  }
]
//报错显示类型无法转换

解决方法

//更改接收参数的方式
 @RequestMapping(value = "/reset_batch", method = RequestMethod.POST)
    public ResultResponse<Boolean> resetSalarySecurityBatch(@RequestBody SalarySecurityListDto salarySecurityList) {
        List<SalarySecurityDto> salarySecurityDtolist = salarySecurityList.getSalarySecurityList();
    }

SalarySecurityListDto实体类

public class SalarySecurityListDto implements Serializable {
    private List<SalarySecurityDto> salarySecurityList;
}

文章来源:https://blog.csdn.net/java_rutu/article/details/139634085
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